-160=-16t^2+144t

Solution for -160=-16t^2+144t equation:

-160=-16t^2+144t

We move all terms to the left:

-160-(-16t^2+144t)=0

We get rid of parentheses

16t^2-144t-160=0

a = 16; b = -144; c = -160;
Δ = b2-4ac
Δ = -1442-4·16·(-160)
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30976}=176$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-144)-176}{2*16}=\frac{-32}{32}
=-1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-144)+176}{2*16}=\frac{320}{32}
=10
$